WebJul 6, 2016 · To make it bit more reusable, you can write a function: from collections import OrderedDict def get_top_players (data, n=2, order=False): """Get top n players by score. Returns a dictionary or an `OrderedDict` if `order` is true. """ top = sorted (data.items (), key=lambda x: x [1] ['score'], reverse=True) [:n] if order: return OrderedDict (top ... WebAug 26, 2011 · You can sort the list using sorted [docs] and take the first five elements: newA = dict (sorted (A.iteritems (), key=operator.itemgetter (1), reverse=True) [:5]) See also: Python Sorting HowTo Share Improve this answer Follow answered Aug 25, 2011 at 21:21 Felix Kling 787k 173 1084 1134 5
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WebApr 28, 2024 · from collections import Counter def Most_Common (lst): data = Counter (lst) return data.most_common (1) [0] [0] Works around 4-6 times faster than Alex's solutions, and is 50 times faster than the one-liner proposed by newacct. On CPython 3.6+ (any Python 3.7+) the above will select the first seen element in case of ties. WebAug 2, 2011 · NumPy proposes a way to get the index of the maximum value of an array via np.argmax. I would like a similar thing, but returning the indexes of the N maximum values. For instance, if I have an array, [1, 3, 2, 4, 5], then nargmax (array, n=3) would return the indices [4, 3, 1] which correspond to the elements [5, 4, 3]. python numpy max
WebList items are indexed and you can access them by referring to the index number: Example Get your own Python Server Print the second item of the list: thislist = ["apple", "banana", "cherry"] print(thislist [1]) Try it Yourself » Note: The first item has index 0. Negative Indexing Negative indexing means start from the end WebOct 20, 2013 · 3 Answers. Sorted by: 4. # reading the file with open (filename, 'r') as infile: lines = list (json.loads (x) for x in infile) # the important part top_10_lines = sorted (lines, key = lambda line : line [3], reverse = True) [0:10] # to write the top 10 file: with open (other_filename, 'w') as outfile: for line in top_10_lines: print (json.dumps ...
WebApr 19, 2024 · A simple solution traverse the given list N times. In every traversal, find the maximum, add it to result, and remove it from the list. Below is the implementation : … WebJun 13, 2015 · However, when I create my list for the max5 values, everything comes out fine using the same method. I am unsure of a function that lets me do this in python. This is just a sample of my problem, my real problem involves store locations along with scores for those stores that I computed from a function, but I want to get the top 5 highest and 5 ...
WebApr 3, 2024 · A simple solution traverse the given list N times. In every traversal, find the maximum, add it to result, and remove it from the list. Below is the implementation : Python3 def Nmaxelements (list1, N): final_list = [] for i in range(0, N): max1 = 0 for j in range(len(list1)): if list1 [j] > max1: max1 = list1 [j] list1.remove (max1)
WebAug 30, 2015 · This will create a list of the 3 largest items, and a list of the corresponding indices: lst = [9,7,43,2,4,7,8,5,4] values = [] values = zip (*sorted ( [ (x,i) for (i,x) in enumerate (f_test)], reverse=True ) [:3] ) [0] posns = [] posns = zip (*sorted ( [ (x,i) for (i,x) in enumerate (f_test)], reverse=True ) [:3] ) [1] streaming donation servicesWebApr 14, 2012 · If you want to get the indices of the three largest values, you can just slice the list. >>> sort_index (score) [:3] [2, 1, 4] It also supports sorting from smallest to largest by using the parameter rev=False. >>> sort_index (score, rev=False) [3, 0, 4, 1, 2] Share Follow answered Nov 5, 2024 at 12:09 Troll 1,859 3 15 33 Add a comment rowan tree coloradoWebJun 14, 2024 · You can also set list elements in this way. For instance: >>> some_list = [1, 2, 3] >>> some_list [-1] = 5 # Set the last element >>> some_list [-2] = 3 # Set the second to last element >>> some_list [1, 3, 5] Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. streaming downloader edgeWebDec 23, 2016 · I need to create anoter list of tuples of the top 5 items from that list of tuples with 5 of the items with the highest quantity bought. For example with the list above it would turn out like this: newItemsQtyBought = [ ('Item no.6', 9), ('Item no.7', 7), ('Item no.3', 3), ('Item no.1', 3), ('Item no.4', 2)] Is there any way to do this? streaming downloadWebDec 22, 2016 · and I want to get the top 5 values from this json. I turn this to list of dictionaries: def changetodict (data): json_str = ast.literal_eval (json.dumps (data)) #common = json.loads (json_str) commonDict = dict (itertools.izip_longest (* [iter (json_str)] * 2, fillvalue="")) print commonDict. This is all the code: import urllib2, mediacloud ... streaming downloader edge extensionrowan tree constructionWebYou can use the max function to find the highest scoring index in each list for example: >>> sublist = [ (0, 0.83094628739162768), (1, 0.084504341129265095), (2, 0.08454937147910728)] >>> index = max (sublist, key=lambda tup: tup [1]) [0] Then you can use map to apply this to all the sublists in your main list: rowan tree condos billings mt